If 75 g of liquid water in a calorimeter changes temperature from 25 degrees C to 75 degrees C how much heat was transferred
1 answer:
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100.133 degree celsius is the boiling point of the solution formed when 15.2 grams of CaCl2 dissolves in 57.0 g of water.
Explanation:
Balanced eaquation for the reaction
CaCl2 + 2H20 ⇒ Ca(OH)2 + HCl
given:
mass of CaCl2 = 15.2 grams
mass of the solution = 57 grams
Kb (molal elevation constant) = 0.512 c/m
i = vont hoff factor is 1 as 1 mole of the substance is given as product.
Molality is calculated as:
molality =
=
= 0.26 M
Boiling point is calculated as:
ΔT = i x Kb x M
= 1 x 0.512 x 0.26
= 0.133 degrees
The boiling point of the solution will be:
100 degrees + 0.133 degrees (100 degrees is the boiling point of water)
= 100.133 degree celcius is the boiling point of mixture formed.
When the enthalpy value is given, we can calculate how much heat is use or produces in a given equation.
67.6 kCal ---> 67.6 kCal= 1 mol of reaction
1 mol of reaction= 1 mol of CO (based on the coefficient)
so 1 mole of CO gives us 67.6 kCal of heat.
calculation:
1 mol CO
67.6 kCal ---> 67.6 kCal= 1 mol of reaction
1 mol of reaction= 1 mol of CO (based on the coefficient)
so 1 mole of CO gives us 67.6 kCal of heat.
calculation:
1 mol CO