Answer:
Y = (x + 3)(x - 4)(x + 1)^2
Y = (x^2 - x - 12)(x^2 + 2x + 1)
Y = x^4 + 2x^3 + x^2 - x^3 - 2x^2 - x - 12x^2 - 24x - 12
Y = x^4 + x^3 - 13x^2 - 25x - 12
Assuming the original price was £1.00
the answer is C) 0.60p
Answer:
8% or 0.08
Step-by-step explanation:
Probability of missing the first pass = 40% = 0.40
Probability of missing the second pass = 20% = 0.20
We have to find the probability that he misses both the passes. Since the two passes are independent of each other, the probability that he misses two passes will be:
Probability of missing 1st pass x Probability of missing 2nd pass
i.e.
Probability of missing two passes in a row = 0.40 x 0.20 = 0.08 = 8%
Thus, there is 8% probability that he misses two passes in a row.
Answer:
15
Step-by-step explanation:
