Answer:
The phrase "opposites attract" is true for atoms. The positively charged ion (cation) and the negatively charged ion (anion) are attracted to each other. It is this attraction, created by the transfer of electrons, that forms the ionic bond. The transfer of one electron creates a single bond.
Explanation:The phrase "opposites attract" is true for atoms. The positively charged ion (cation) and the negatively charged ion (anion) are attracted to each other. It is this attraction, created by the transfer of electrons, that forms the ionic bond. The transfer of one electron creates a single bond.
By unit conversion, the aspirin contains 7.72 grains.
We need to know about unit conversion to solve this problem. The unit conversion can be used to convert a unit to another unit. It can be defined as
a = xb
where a is unit a, b is unit b and x is the constant of conversion.
From the question above, we know that
m = 0.5 gram
unit conversion
(1 grain = 64.8 mg)
Convert the unit conversion to 1 mg
1 grain = 64.8 mg
1/64.8 grain = 64.8/64.8 mg
1 mg = 1/64.8 grain
Convert the aspirin mass to grain
m = 0.500 g
m = 0.5 x 10³ mg
m = 0.5 x 10³ x 1/64.8 grain
m = 7.72 grain
Find more on unit conversion at: brainly.com/question/4158962
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<h3>
Answer:</h3>
42960 years
<h3>
Explanation:</h3>
<u>We are given;</u>
- Remaining mass of C-14 in a bone is 0.3125 g
- Original mass of C-14 on the bone is 80.0 g
- Half life of C-14 is 5370 years
We are required to determine the age of the bone;
- Remaining mass = Original mass × 0.5^n , where n is the number of half lives.
Therefore;
0.3125 g = 80.0 g × 0.5^n
3.90625 × 10^-3 = 0.5^n
- Introducing logarithm on both sides;
log 3.90625 × 10^-3 = n log 0.5
Solving for n
n = log 3.90625 × 10^-3 ÷ log 0.5
= 8
- Therefore, the number of half lives is 8
- But, 1 half life is 5370 years
- Therefore;
Age of the rock = 5370 years × 8
= 42960 years
Thus, the bone is 42960 years old
Answer:
Explanation:
Butane is an alkane and has no multiple bond in it.
The isomers of butane are
a) n-butane
b) t-butane
The structures are shown in the figure.
The most stable radical will be tertiary butyl radical.
The structures are shown in figure.