<u>Answer:</u> The freezing point of solution is 2.6°C
<u>Explanation:</u>
To calculate the depression in freezing point, we use the equation:
Or,
where,
=
Freezing point of pure solution = 5.5°C
i = Vant hoff factor = 1 (For non-electrolytes)
= molal freezing point depression constant = 5.12 K/m = 5.12 °C/m
= Given mass of solute (anthracene) = 7.99 g
= Molar mass of solute (anthracene) = 178.23 g/mol
= Mass of solvent (benzene) = 79 g
Putting values in above equation, we get:
Hence, the freezing point of solution is 2.6°C
Answer:
You have been asked to draw a Bohr model of the element carbon. How would you arrange the dots that represent electrons? They would be embedded in a solid core. They would be in rings around the nucleus
Answer:
Part a: <em>Units of k is </em><em> where reaction is first order in A and second order in B</em>
Part b: <em>Units of k is </em><em> where reaction is first order in A and second order overall.</em>
Part c: <em>Units of k is </em><em> where reaction is independent of the concentration of A and second order overall.</em>
Part d: <em>Units of k is </em><em> where reaction reaction is second order in both A and B.</em>
Explanation:
As the reaction is given as
where as the rate is given as
where x is the order wrt A and y is the order wrt B.
Part a:
x=1 and y=2 now the reaction rate equation is given as
Now the units are given as
The units of k is
Part b:
x=1 and o=2
x+y=o
1+y=2
y=2-1
y=1
Now the reaction rate equation is given as
Now the units are given as
The units of k is
Part c:
x=0 and o=2
x+y=o
0+y=2
y=2
y=2
Now the reaction rate equation is given as
Now the units are given as
The units of k is
Part d:
x=2 and y=2
Now the reaction rate equation is given as
Now the units are given as
The units of k is
3Fe(s) + 4H2O(l) — 1Fe3O4(s) + 4H2(g)
Answer:
Na₂O will also form a brittle ionic compound.
Explanation:
Sodium is located in the same group as Potassium: Alkali Metals. This is because both elements have similar chemical properties. In term of their electronegativity, both elements are very close. Na has an electronegativity of 0.93, while K has an electronegativity of 0.82. This makes both ideal elements to create ionic compounds with Oxygen.