Answer:
do you have a picture of this
Given end points of diameter,
(x1,y1)=(-3,-4)
(x2,y2)=(0,0)
Now,
the equation of circle is,
(x-x1)(x-x2)+(y-y1)(y-y2)=0
or, (x+3)(x-0)+(y+4)(y-0)=0
or, x^2 +3x +y^2 +4y =0
or, x^2 +y^2 +3x + 4y=0
which is in the form of x^2 +y^2 +2gx +2fy + c=0
where,
g=3/2
h=2
c=0
Now,
Answer:
(b)
P = [4(4a + 3b]/(2a + b)
Step-by-step explanation:
P = 2L + 2W
P = [2(5a + 4b) + 2(3a + 2b)]/(2a + b)
P = [10a + 8b + 6a + 4b]/(2a + b)
P = [16a + 12b]/(2a + b)
P = [4(4a + 3b]/(2a + b)