The three consecutive integers are: x, (x+1) and (x+2).
We can suggest this equation:
x+(x+1)+(x+2)=126
3x+3=126
3x=126-3
3x=123
x=123/3
x=41
x=41
(x+1)=41+1=42
(x+2)=41+2=43
Answer: the three consecutive integers would be: 41,42 and 43.
The correct answer is 3/8
Rewriting our equation with parts separated
1+7/8−6/4
Solving the fraction parts
7/8 - 6/4?
Find the LCD of 7/8 and 6/4 and rewrite to solve with the equivalent fractions.
LCD = 8
7/8−1 2/8=−58
7
8
−
12
8
=
−
5
8
Combining the whole and fraction parts
1−5/8=3/8
Answer:
20%
Step-by-step explanation:
6x5=30
20x5=100