2 years ago

18)

1 answer:

8 0

The answer is option D, limiting reactant.

Oftentimes in chemistry, there are leftovers of certain chemicals in reactions. When not all of a certain reactant is used up in a reaction, it is known as the excess reactant (since there is an excess of it). The reactant that's completely used up is known as the limiting reactant (since it limits the reaction from going any further)

-T.B.

You might be interested in

Which of the following is the main disadvantage to using fossil fuels?

steposvetlana [31]

The answer is A)pollution

7 0

2 years ago

Read 2 more answers

What percentage of carpet is calcium carbonates?

e-lub [12.9K]

Answer:

the percentage of carpet is calcium carbonates is 12.456734190

5 0

2 years ago

How can we regain the hardness of water by adding lime?

Maru [420]

Answer:

due to the bicarbonate of CaCO3

5 0

2 years ago

Read 2 more answers

The elements least likely to form bonds are found in which group? 15, 16, 17, 18

Ipatiy [6.2K]

Answer:

D.18

Explanation:

Edgenuity

3 0

2 years ago

Read 2 more answers

19.3 g of cadmium hydroxide reacted with 15.21 g of hydrobromic acid. How many grams of water can be made?

Alecsey [184]

Answer:

$m_{H_2O}=3.384gH_2O$

Explanation:

Hello,

In this case, the chemical reaction is:

$Cd(OH)_2+2HBr\rightarrow CdBr_2+2H_2O$

Thus, we first identify the limiting reactant by computing the yielded moles of water by both of the reactants:

$n_{H_2O}^{by\ Cd(OH)_2}=19.3gCd(OH)_2*\frac{1molCd(OH)_2}{146.4gCd(OH)_2}*\frac{2molH_2O}{1molCd(OH)_2}=0.264molH_2O\\\\n_{H_2O}^{by\ HBr}=15.21gHBr*\frac{1molHBr}{80.9gHBr}*\frac{2molH_2O}{2molHBr}=0.188molH_2O$

In such a way, since HBr yields less water than cadmium hydroxide, we infer that HBr is the limiting one, therefore, the yielded mass of water are:

$m_{H_2O}=0.188molH_2O*\frac{18gH_2O}{1molH_2O}\\ \\m_{H_2O}=3.384gH_2O$

Regards.

4 0

2 years ago