Answer:
hello there
ok so the answer is 4 + 
Step-by-step explanation:
hope this helps!
Answer:
The answer is B
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....
Answer:
5/32
Step-by-step explanation:
If a coin if flipped five times with four heads, then it has exactly one tail. The number of way to arrange four heads and one tail are as follows:
T H H H H
H T H H H
H H T H H
H H H T H
H H H H T
Essentially, there are five way because there are five "positions" where the tail could be.
Then, you need to find the total amount of possibilities for flipping a coin five times. Every time you flip it, there are two possibilities- heads and tails. Therefore, for five flips, the total amount of possibilities is
2x2x2x2x2 = 32
You know that
probability= # of desired outcome
----------------------------------
# of total outcomes
So the probablity is 5/32.
