Answer: 4.6 is the answer to 1.38 divided by 0.3=4.6
So we want to solve like if it was just a basic equation. We start with 25+3.50x<17+7.50x and get rid of our smallest x. That means we get rid of the 3.50x by subtracting from both sides and our new equation is 25<17+4x. Let’s get our x by itself shall we, so let’s subtract 17 from both sides and we get 8<4x. Finally all we do is divide by 4 and just like that 2
Answer:
B. Alex smokes a pack of cigarettes per day even though he knows that he may face poor health down the road because of his smoking habit.
Step-by-step explanation:
Time preference means that the person would like to have temporary but instant satisfaction. In this case, B would be the best choice, for Alex wants to experience the "high" (I guess?) from smoking, even when he knew that there would be health consequences down the road.
In this case, it is not:
A, for Thomas is not going to receive his reward (a profit from the investment) until later on. The money he invest is still "there", but it is technically gone into investment.
C, because this is assuming that retirement is a long way off, and that this would be a long-term investment, rather than a short term.
D, this is a long-term investment, as Sarah "hopes" that she can earn it all back in the future. With what she learns, she, in the long run, wants to find a sustainable & high-paying job.
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If Jackson went to the movies and payed $7 initially for his ticket and then payed $2 for each box of candy that he buys, then the equation could look like this: y = 2x + 7, where y represents the total cost and x represents the number of boxes of candy Jackson buys.
Answer:
The man covers 200 ft in 40 seconds.
Step-by-step explanation:
A person is moving on the sidewalk from one end to the other end.
He walks 40 feet in 8 seconds.
Therefore his speed = 
= 
= 5 ft/
He covers the sidewalk distance at a rate of 5 feet every second.
To calculate the time taken to cover 200 ft,
time = 
time =
<u>time = 40 seconds</u>
Hence the man covers 200 ft in 40 seconds.
