0:3:1
Explanation:
Tasters have the dominant allele for the itter taste of PTC, they can be homozygous TT and heterozygous Tt.
Non-tasters are supposed as autosomal recessive characters
they are homozygous recessive tt when expressed
Given in the equation two heterozygotes parents would produce offspring with the trait in the following ratio.
Tt (parent 1)
Tt (parent 2)
If a punnet square is made
T t
T TT Tt
t Tt tt
The phenotypic character is in the ratio of 0:3:1
There will be 25% chances of recessive trait of non-tasters in the progeny of heterozygous parents.
B because theyre in order of the number of protons
Answer:
Option B, not phosphorylated; inhibited
Explanation:
Glucose 6 acts as a catobolite repressant . A catobolite repressant which is usually a carbon compound inhibits the operon transcription. In the presence of glucose -6, unphosphorylated enzyme IIAGlc inhibits the transportation system and hence prevents the utilization of lactose. Glucose‐6‐phosphate and other non‐PTS carbon causes inducer exclusion thereby leading to dephosphorylation of enzyme IIAGl without getting transported.
Hence, option B is correct
Glucose or fructose. In glycolysis, glucose is oxidized to be pyruvate.