$We\ are\ given\ that,\\4^4*4^{-8}*4\\We\ know\ that,\ for\ any\ real\ number\ n, n^a*n^b=n^{(a+b)}\\Hence,\\First,\ lets\ write\ all\ the\ terms\ in\ an\ exponential\ form.\\4^4*4^{-8}*4^1\\=4^{(4+(-8)+1)}\\=4^{(5-8)}\\=4^{-3}$

5 0

2 years ago

Help me plz branniest to whoever is right

nataly862011 [7]

Answer:

-3,8

Step-by-step explanation:

8 0

2 years ago

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Draw or write to explain why 1 hundred 4 tens and 14 tens name the same amount

mihalych1998 [28]

1 hundred can also be 10 tens so when you add 10 tens and 4 tens you 14 tens and that is the same thing as 14 tens

7 0

2 years ago

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