You compress a spring by a distance of 0.2 m. The spring has a spring constant of 37 N/m. When you release the spring, it snaps
2 answers:
At that point it is no longer trying to uncompress nor is it trying to stretch. This is the same thing as a pendulum at the bottom of its swing, no longer falling but not yet rising against gravity. Thus the kinetic energy there is the same as the potential energy when it is compressed. The energy of compression is
This gives E=0.5(37)(0.2)²=0.74J
This is the same as the kinetic energy when it is at natural length
This gives E=0.5(37)(0.2)²=0.74J
This is the same as the kinetic energy when it is at natural length
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Answer:
3.71 m/s
Explanation:
From the law of conservation of linear momentum, since we are neglecting minor energy losses due to friction then we can express it as since all the potential energy is transformed to kinetic energy
Making v the subject of the formula then and here m is the mass of the block, g is acceleration due to gravity, h is the height. Substituting 0.7 m for h and 9.81 for g then we obtain that