Answer:
Q1: NO
Q2: NO
Explanation:
Step 1: Given data
Percentage by mass of nitrogen: 46.68%
Percentage by mass of oxygen: 53.32%
Step 2: Divide each percentage by the mass of the element
N: 46.68/14.01 = 3.332
O: 53.32/16.00 = 3.332
Step 3: Divide both numbers by the smallest one (in this case is the same)
N: 3.332/3.332 = 1
O: 3.332/3.332 = 1
The empirical formula is NO. Its molar mass is 30.01 g/mol.
Step 4: Calculate "n"
n = molar mass of the molecular formula / molar mass of the empirical formula
n = (30.01 g/mol) / (30.01 g/mol) = 1
Step 5: Determine the molecular formula
We do so by multiplying the empirical formula by "n".
NO × 1 = NO
