43 degrees because they are congruent so angle p is equal to angle k
The height of flagpole is 12.5 feet.
Step-by-step explanation:
Given,
Height of woman = 5 foot
Shadow of woman = 6 feet
Ratio of height to shadow = 5:6
Shadow of flagpole = 15 foot
Height of flagpole = x
Ratio of height to shadow = x:15
Using proportion;
Ratio of height to shadow :: Ratio of height to shadow
Product of mean = Product of extreme
Dividing both sides by 6
The height of flagpole is 12.5 feet.
Keywords: ratio, proportion
Learn more about proportion at:
#LearnwithBrainly
Answer:
Check the explantion
Step-by-step explanation:
H(t) represent the height of the ball after t seconds.
1)
In order to figure the maximum height of the ball we must minupulate this equation into a form where we can easily find the maximum height.
We can also see this parabola will be downward concaved because it has a negative coefficent for the t^2 term.
a) Let's Manipulate!
Vertex form is a form where we can easily tell the maximum and minimum points. To get in into Vertex form we just need to complete the sqaure.
Lets reanrage the terms
h(t)= -16t^2+144t
Undo the distrubitive propety
h(t)= -16(t^2-9t+20.25)+324
Add and subtract 324.
h(t) = -16(t-4.5)^2+324
COmplete the square.
b) Almost done!
We can now see that the stuff with the brackets is always positive/zero because any real number sqaured is a positive/zero. But than we multiply the positive stuff by a negative number (-16) so its now all negative.
The only exception is when its zero.
And off course if we add 324 to zero its always going to be greater than 324 + a negative number. To get the first term to be zero we can have t = 4.5.
c) Proove it!
h(4.5) = -16(4.5-4.5)^2+324
=324
d) Double Check by graphing!
(Its a attach screenshote by the way)
e) Answer:
The ball will reach its maximum height after 4.5 seconds.
Hoped this helped!,
JoeLouis2
25×7=175
____<u>20</u>__________<u>5</u>____
| 140 | 35 | 7
| | |
Answer:
See below for the graph.
Step-by-step explanation:
A circle or ellipse can be defined using the same sort of equation. Here, we have chosen to use the formulation ...
... ((x -a)/p)^2 +((y -b)/q)^2 -1 = 0
This will be the general form of the equation for an ellipse with center (a, b) and semi-axes p and q, in the x- and y-directions, respectively. When the axes are the same length, the ellipse is a circle.
By defining the function ...
... c(a, b, p, q, x, y) = ((x -a)/p)^2 +((y -b)/q)^2 -1
we can use the same function for all of the circles/ellipses in the figure. The parabola has vertex (0, -6) and a vertical scale factor of -1, so it can be formulated using the vertex form:
... y = k(x -a)^2 +b . . . . . for vertex (a, b) and vertical scale factor k.
_____
<em>The equations</em>
- (x/6)² +(y/6) -1 = 0
- (x+2)² +(y-2)² -1 = 0
- (x-2)² +(y-2)² -1 = 0
- (x/3)² +(y+2)² -1 = 0
- y = -x² -6