Answer:
High conductivity
Explanation:
Metals exhibit high conductivity due to the mobility of valence electrons.
Answer:
The answer would be A
Explanation:
If more solvent is added, the solution becomes unsaturated because in principle it is capable of dissolving more solute.
It is the 4th one that is correct and balanced
Answer:
2CO₂ ⇄ 2CO + O₂.
Explanation:
- <em>The equilibrium constant (Keq)</em> for a reaction is the ratio of the concentration of the products to the reactants, each one is raised to each molar coefficient.
So, for Keq = [CO]²[O₂]/[CO₂]²,
It is clear that the products are CO and O₂, while the reactant is CO₂.
So, the reaction for this is:
<em>2CO₂ ⇄ 2CO + O₂.</em>
Ecell = E°cell - RT/vF * lnQ
R is the gas constant: 8.3145 J/Kmol
T is the temperature in kelvin: 273.15K = 0°C, 25°C = 298.15K
v is the amount of electrons, which in your example seems to be six (I'm not totally sure)
F is the Faradays constant: 96485 J/Vmol (not sure about the mol)
Q is the concentration of products divided by the concentration of reactants, in which we ignore pure solids and liquids: [Mg2+]³ / [Fe3+]²
Standard conditions is 1 mol, at 298.15K and 1 atm
To find E°cell, you have to look up the reduction potensials of Fe3+ and Mg2+, and solve like this:
E°cell = cathode - anode
Cathode is where the reduction happens, so that would be the element that recieves electrons. Anode is where the oxidation happens, so that would be the element that donates electrons. In your example Fe3+ recieves electrons, and should be considered as cathode in the equation above.
When you have found E°cell, you can just solve with the numbers I gave you.