25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer:
x = 17
Step-by-step explanation:
1) Make the bases the same then rewrite.
4 = 2²
2^2(2x - 5) = 2^3x + 7
2) Since the bases are the same, set the exponents equal to each other.
2(2x -5) = 3x + 7
4x - 10 = 3x + 7
4x - 3x = 7 + 10
x = 17
Whoever put this problem is smarttttttttttt
Answer:
#1- z = 75
#2- t = 1.33
Step-by-step explanation:
<em>HOPE THIS HELPS!!! </em><em>:)</em>
Your two equations are at the top, in the box is what each variable represents. Below the box is total liters of the 15%, which is going to equal the total liters for 10% plus the total liters for 25%. Make your percentages into decimals. There’s a total of 30 liters so, x+y needs to equal 30. Isolate a variable, I chose y, you can do either or (isolating x would be more math). Y is going to equal 30-x, substitute that for the Y in the second equation, then you need to distribute 0.25 into 30-x. Then it’s simple math, subtract 7.50 from both sides, add like gets, divide both sides by -0.15, making x=20.
