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2 years ago

Help pleaseee! Relationships within triangles posttest

Mathematics

1 answer:

maksim [4K]2 years ago

4 0

It’s 88 cause if you see in the other side is 44+44 and what does That Equal =88

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The quadratic function f (x) = - 45x2 + 350x + 1,590 models the population of a city where x represents the number of years sinc

kramer

Answer: 2,215,000

Step-by-step explanation:

Given: The quadratic function $f (x) = - 45x^2 + 350x + 1,590$ models the population of a city where x represents the number of years since 2005.

To Find: population of the city in 2010

We need to put x= 2010-2005 = 5

$f (5) = - 45(5)^2 + 350(5) + 1,590\\\\=-1125+1750+1590 =2215$

Hence, the estimated population of the city in 201 = 2215 thousands or 2,215,000 .

3 0

2 years ago

Find mFE A) 52° C) 76° B) 93° D) 112°

mixer [17]

Answer:

76 degrees

Step-by-step explanation:

GE = 180 since it is a straight line

GE = GR + FE

180 = 7x+6 +6x-8

Combine like terms

180 = 13x-2

Add 2 to each side

182 = 13x

Divide by 13

182/13 = 13x/13

14 =x

We want FE

FE = 6x-8

FE = 6(14) -8

=84 -8

=76

3 0

2 years ago

Write down the explicit solution for each of the following: a) x’=t–sin(t); x(0)=1

Kay [80]

Answer:

a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)

Step-by-step explanation:

Let's solve by separating variables:

$x'=\frac{dx}{dt}$

a) x’=t–sin(t), x(0)=1

$dx=(t-sint)dt$

Apply integral both sides:

$\int {} \, dx=\int {(t-sint)} \, dt\\\\x=\frac{t^2}{2}+cost +k$

where k is a constant due to integration. With x(0)=1, substitute:

$1=0+cos0+k\\\\1=1+k\\k=0$

Finally:

$x=\frac{t^2}{2} +cos(t)$

b) x’+2x=4; x(0)=5

$dx=(4-2x)dt\\\\\frac{dx}{4-2x}=dt \\\\\int {\frac{dx}{4-2x}}= \int {dt}\\$

Completing the integral:

$-\frac{1}{2} \int{\frac{(-2)dx}{4-2x}}= \int {dt}$

Solving the operator:

$-\frac{1}{2}ln(4-2x)=t+k$

Using algebra, it becomes explicit:

$x=2+ke^{-2t}$

With x(0)=5, substitute:

$5=2+ke^{-2(0)}=2+k(1)\\\\k=3$

Finally:

$x=2+3e^{-2t}$

c) x’’+4x=0; x(0)=0; x’(0)=1

Let $x=e^{mt}$ be the solution for the equation, then:

$x'=me^{mt}\\x''=m^{2}e^{mt}$

Substituting these equations in c)

$m^{2}e^{mt}+4(e^{mt})=0\\\\m^{2}+4=0\\\\m^{2}=-4\\\\m=2i$

This becomes the solution m=α±βi where α=0 and β=2

$x=e^{\alpha t}[Asin\beta t+Bcos\beta t]\\\\x=e^{0}[Asin((2)t)+Bcos((2)t)]\\\\x=Asin((2)t)+Bcos((2)t)$

Where A and B are constants. With x(0)=0; x’(0)=1:

$x=Asin(2t)+Bcos(2t)\\\\x'=2Acos(2t)-2Bsin(2t)\\\\0=Asin(2(0))+Bcos(2(0))\\\\0=0+B(1)\\\\B=0\\\\1=2Acos(2(0))\\\\1=2A\\\\A=\frac{1}{2}$

Finally:

$x=\frac{1}{2} sin(2t)$

7 0

2 years ago

Is 0.919191 a terminating or repeating decimal

nydimaria [60]

Repeating because its repeating 91.

6 0

2 years ago

Will give brainliest and 5 stars if correct. How does Shakespeare manipulate language?

lions [1.4K]

Answer:

Shakespeare uses the language of the characters to achieve this multifaceted quality. Through the use of language (specifically Iago, Othello, and Desdemona), Shakespeare propels the plot, engages the audience, creates dramatic irony, and reveals the characters’ psyches.

7 0

2 years ago

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