Using the graph provided with the question, we are able to find that that for a concentration of 270 micromol per kilogram, the calcification rate is 20 mmol calcium carbonate per meter squared per day.
Using this calcification rate,
30 = 20 * 1 * days
days = 1.5
The deposition will require 1.5 days.
<span>Tri- in phosphate meand three. Tri- is formed from the Latin word "tres" and Greek word "treis".It is usually used in the beginning of nouns and adjectives that have three as part of their meaning.In chemistry, it means having three atoms, groups or equivalents.</span>