(3) The frictional force exerted by the floor on the box
Collision domain is a portion in the network where there is a possibility of formation of packets. This occurs when two or more devices are able to send a packet to a single switch or port on the network that is shared, on the same time. It was noted that this collision domain reduces the efficiency of the network.
For this item, the first packet is the whole switch with the three devices. Next one would be first of the three devices that is connected to the other port. Similarly, the third one would be the second of the three devices that is also connected to the switch. Therefore, the answer is 3.
I think its all four of them could be wrong but try all four !!!!!!
Answer:
<h2>1567.09 N/m</h2>
Explanation:
Step one:
given data
mass m=5kg
compression x= 3.13cm to m= 0.0313m
<em>According to Hooke's law, provided the elastic limit of an elastic material is not exceeded the extension e is directly proportional to the applied force</em>
F=ke
where
k= spring constant in N/m
e= extension/compression in
Step two:
assume g= 9.81m/s^2
F=mg
F=5*9.81
F=49.05N
substitute in the expression F=ke
49.05=k*0.0313
k=49.05/0.0313
k=1567.09 N/m
<u>The force constant (in N/m) of the spring is 1567.09 N/m</u>
The density of an object can be calculated using the formula Density = Mass/Volume. In this case however we are searching for the volume and must rearrange the formula so that we are solving for the volume. If you multiply both sides by volume and then divide both sides by mass you end up with the equation Volume = Mass/Density.
Volume = 1500g/1.5g/cm^3
Volume = 1000 cm^3
