Answer:
the photo is a little blurry I cannot answer the question unfortunately sorry
3x²-y³ - y³ - z if x = 3, y = -2, z = -5
Simply plug in all the values :)
3(3²) - (-2³) - (-2³) - (-5)
Simplify.
3(9) + 2³ + 2³ + 5
Simplify.
27 + 8 + 8 + 5
Simplify.
35 + 13
Simplify.
48
~Hope I helped!~
Answer:
<em>Martin saved $75 on the television because of the sale</em>
Step-by-step explanation:
<u>Equations</u>
Let's call x=the original price of the television (before discount).
The television had been on sale for 25% off, this means the discount was:
25% of x = = 0.25x
The sale price was the original price minus the discount:
x - 0.25x = 0.75x
This is what Martin paid, thus:
0.75x = 225
Dividing by 0.75:
x = 225 / 0.75
x = $300
The original price of the television was $300, and the discount was:
0.25*$300 = $75
Martin saved $75 on the television because of the sale
Answer:
1/15
Step-by-step explanation:
(1). <em>Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD (Least Common Denominator). </em>
So lets do step one now, the LCD is 15 so we have to make both denominators agree on one number, so 15 is the number both denominators agree on.
Solve:
2*3/5*3 - 1*5/3*5
(2). <em>Complete the multiplication.</em>
6/15 - 5/15
(3). <em>The two fractions now have like denominators so you can subtract the numerators.</em>
6 - 5 / 15 - 15 = 1/15
*Pro tip:
<em>The denominator doesn't change and stays the same. So you don't </em>
<em>subtract the 15 by 15.</em>
(4). <em>Then you'll get the answer and then if you can simplify then simplify.</em>
<em />
The Answer is 1/15, and cannot be simplified.
So the answer is 1/15
Hope this helps!
All you have to do is substitute the y value from the 1st equation into the second equation and solve...
a) y= 2-x
5x + 4y = 5
Substitute (2-x) into the second equation anywhere there is a y...
5x + 4y = 5
5x + 4(2-x) = 5
Now solve
5x + 8 - 4x = 5
5x - 4x + 8 = 5
x + 8 = 5
x = -3
Now that you have a solution for x, substitute -3 into either of the original equations anywhere there is an x then solve for y...
y = 2 - x
y = 2 - (-3)
y = 2+3 = 5
You solved for x and got -3 and solved for y and got 5, so your solution set is
(-3, 5).
Now check it by substituting both numbers into one of the original equations and you should have a true statement if it is correct...
y = 2 - x
5 = 2 - (-3)
5 = 2+3
5 = 5
True statement... it checks!
note* during the check, if the equation would have worked out to something like 2 = 5, then that is a false statement therefore the solution set would be wrong and you'd have to go back and find the mistake.