What is the 9th term of the geometric sequence 5 -25 125
1 answer:
Answer:
Step-by-step explanation:
hello :
the n-ieme term is : An=A1×r^(n-1)
A1 the first term r : the common ratio
in this exercice : A1 =5 r = 125/-25=-25/5 = - 5 n = 9
A9=5×(-5)^(9-1) = 5×5^8 = 5^9 because : ((-5)^(8)= 5^8)
You might be interested in
Answer:
2x^2=-8
2x^2/2=-8/2
x^2=-4
x=2
Step-by-step explanation:
HOPE THAT THIS IS HELPFUL.
HAVE AN AWESOME DAY.
Answer:
6
Step-by-step explanation:
Chipped toothed
Bit of a potato
Let's hope ya don't get fried
And the dentist on the phone
D is the answer just took test
Answer:
= 5u
Step-by-step explanation:
You combine like terms
( 2u+ 8u = 10u )
( -5u + 10 u =5u)
