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2 years ago

The area of square abcd is 7cm^2 show that x^2+4x=3

Mathematics

1 answer:

AveGali [126]2 years ago

4 0

Answer:

see explanation

Step-by-step explanation:

The area (A) of the square = s² ( s is the measure of the side )

Here s = x + 2 and A = 7 , thus

(x + 2)² = 7 ← expand left side using FOIL

x² + 4x + 4 = 7 ( subtract 4 from both sides )

x² + 4x = 3 ← as required

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Select all the points that are on the graph of the line LaTeX: 2x + 4y = 202 x + 4 y = 20.

liraira [26]

Answer:

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Step-by-step explanation:

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2 years ago

Write the number in word form: (2 x 300) + (5 x 10) +(5 x 1) + (4 x 0.2) + (3 x 0.04)

Lerok [7]

Answer:

six hundred fifty-five and ninety-two hundredths

Step-by-step explanation:

655.92

Hope this helps.

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2 years ago

Read 2 more answers

From families with four children a family is chosen at random. Let X be the number of boys in the family. Calculate and sketch t

alisha [4.7K]

Solution :

Given :

X = the number of boys in a family of four children

Families having four children are chosen randomly.

The gender distribution in the four child family are equally probable.

Thus,

X P(X) CDF

0 $^4C_0 (1/2)^{4}$ = 1/16 $\frac{1}{16}$

1 $^4C_1 (1/2)^{4}$ = 1/4 $\frac{5}{16}$

2 $^4C_2 (1/2)^{4}$ = 3/8 $\frac{11}{16}$

3 $^4C_3 (1/2)^{4}$ = 1/4 $\frac{15}{16}$

4 $^4C_4 (1/2)^{4}$ = 1/16 1

4 0

2 years ago

10 POINTS AND BRAINLIEST<br> URGENT MATH QUESTION SEE PICTURE

Lostsunrise [7]

The point-slope form:

$y-y_1=m(x-x_1)$

$m$ - slope

$(x_1,\ y_1)$ - point

We have the point $(3,\ -2)\to x_1=3,\ y_1=-2$ and the slope $m=\dfrac{2}{3}$

Substitute:

$y-(-2)=\dfrac{2}{3}(x-3)\\\\\boxed{y+2=\dfrac{2}{3}(x-3)}$

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2 years ago

2.5% of a population are infected with a certain disease. There is a test for the disease, however the test is not completely ac

Aleks04 [339]

Answer:

$P(disease/positivetest) = 0.36116$

Step-by-step explanation:

This is a conditional probability exercise.

Let's name the events :

I : ''A person is infected''

NI : ''A person is not infected''

PT : ''The test is positive''

NT : ''The test is negative''

The conditional probability equation is :

Given two events A and B :

P(A/B) = P(A ∩ B) / P(B)

$P(B) >0$

P(A/B) is the probability of the event A given that the event B happened

P(A ∩ B) is the probability of the event (A ∩ B)

(A ∩ B) is the event where A and B happened at the same time

In the exercise :

$P(I)=0.025$

$P(NI)= 1-P(I)=1-0.025=0.975\\P(NI)=0.975$

$P(PT/I)=0.904\\P(PT/NI)=0.041$

We are looking for P(I/PT) :

P(I/PT)=P(I∩ PT)/ P(PT)

$P(PT/I)=0.904$

P(PT/I)=P(PT∩ I)/P(I)

0.904=P(PT∩ I)/0.025

P(PT∩ I)=0.904 x 0.025

P(PT∩ I) = 0.0226

P(PT/NI)=0.041

P(PT/NI)=P(PT∩ NI)/P(NI)

0.041=P(PT∩ NI)/0.975

P(PT∩ NI) = 0.041 x 0.975

P(PT∩ NI) = 0.039975

P(PT) = P(PT∩ I)+P(PT∩ NI)

P(PT)= 0.0226 + 0.039975

P(PT) = 0.062575

P(I/PT) = P(PT∩I)/P(PT)

$P(I/PT)=\frac{0.0226}{0.062575} \\P(I/PT)=0.36116$

8 0

2 years ago