Let's plug x= -1, y= 4 in the inequation, we have:
4< 2*(-1)+5
⇒ 4< -2+5
⇒ 4< 3 (false)
Therefore, (-1,4) is not a solution of the inequation y<2x+5~
If line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The line AB and BC are intersecting at point B.
Ray BD bisect the angle ABC
∠ABD = x+8 degrees
∠ABD=∠DBC = x+8
Because the ray BD bisect the ∠ABC, so ∠ABD and ∠DBC will be equal
∠ABD+∠DBC= 4x-30 degrees
Because both are vertically opposite angles
Substitute the values in the equation
x+8 + x+8 = 4x-30
2x+16 = 4x-30
2x-4x = -30-16
-2x = -46
x = 23
Hence, if line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The complete question is
Line AB and BC are intersecting at point B and ray BD bisect the angle ABC. What is the value of x?
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Answer:
isosceles trapezoid
Step-by-step explanation:
1) find the distance of the points
AB =
BC = |7-4| = 3
CD =
AD = |9-2| = 7
2) equation of the line that passes threw BC
y = 7
3) equation of the line that passes threw AD
y = 5
conclusion
the quadrilateral has two parallel sides and two congruent sides, so it is a isosceles trapezoid
Answer:
y - 12 = 9(x - 4)
Step-by-step explanation:
The vertex (h, k) is (4, 12) and the point (5, 21) is on the graph. Assuming that this is a vertical parabola, opening up (because the coordinate 21 is greater than the coordinate 12), we insert the knowns into y - k = a(x - h)^2, obtaining
21 - 12 = a(5 - 4), or 9 = a. With a known, we can write the desired equation:
y - 12 = 9(x - 4)
The answer is
Y=3(x-3)(x+5)