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2 years ago

Albert is traveling 60 mph in his car. After 3 hours, how far will he have traveled?

Mathematics

2 answers:

AfilCa [17]2 years ago

7 0

60 mph. Mph means miles per hour. So if it was 3 hours just do 60 x 3 to get your answer. 60 x 3 = 180

ANSWER: 180

Dahasolnce [82]2 years ago

6 0

He will have traveled 180 miles, though with real situations the distance may vary.

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To make green paint, students mixed yellow paint with blue paint. The table below shows how many yellow and blue drops from a dr

stellarik [79]

Answer:

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2 years ago

A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confid

katrin [286]

Answer:

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 865, \pi = \frac{408}{865} = 0.4717$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 - 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.4384$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 + 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.5050$

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

6 0

2 years ago

The perimeter it a square field is 224. How long is

geniusboy [140]

Since each side of a sqare is equal and there are four sides to the square
$224 = 4x$
X being the side length.
Then you would simiply divide by 4 to isolate x
$x = 56$
A side length is 56

8 0

2 years ago

Novay_Z [31]

Answer:

The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the <u>line y = x</u> and a translation <u>10 units right and 4 units up</u>, equivalent to T₍₁₀, ₄₎

Step-by-step explanation:

For a reflection across the line y = -x, we have, (x, y) → (y, x)

Therefore, the point of the preimage A(-6, 2) before the reflection, becomes the point A''(2, -6) after the reflection across the line y = -x

The translation from the point A''(2, -6) to the point A'(12, -2) is T(10, 4)

Given that rotation and translation transformations are rigid transformations, the transformations that maps point A to A' will also map points B and C to points B' and C'

Therefore, a sequence of transformation maps ΔABC to ΔA'B'C'. The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the line y = x and a translation 10 units right and 4 units up, which is T₍₁₀, ₄₎

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2 years ago

What is the sum of an infinite geometric series if the first term is 81 and the common ratio is 2⁄3?

Marrrta [24]

the sum to infinity of a geometric series = $\frac{a}{1-r}$

where a is the first term and r the common ratio

= $\frac{81}{\frac{1}{3} }$ = 81 × 3 = 243

4 0

2 years ago