In the first cross one of the parent has only dominant allele and one has only recessive allele that means the offspring in F1 will be 100% heterozygous
XxYyZz
the gametes resulted from this individual are
XYZ XYz XyZ Xyz xYZ xYz xyZ xyz
it produces 8 types of gamets one of which is xyz the proportion is 1/8
Question in English:
A female carries a recessive lethal gene (l) on one of her X chromosomes, and a normal dominant allele (L) on the other. What is the sex ratio to be expected in this woman's dependency if she marries a normal man?
Answer:
2/3 females
1/3 males
Explanation:
Females have two X chromosomes (XX) and males have an X and a Y chromosome (XY).
The genotype of the female is XLXl. The genotype of the male is XLY, since he is normal.
The possible genotypes are:
<u> XL Xl</u>
<u>XL</u> <em>XLXL XLXl</em>
<u>Y</u> <em>XLY </em><em>XlY</em>
<em />
All female offspring will be normal as they will always have one normal copy of the X chromosome from their father.
50% of the male offspring will be normal, but 50% will inherit the lethal gene from their mother.
Because the allele is lethal, that means XlY males will not be born.
That means 2/3 of the children will be females, and 1/3 will be males.
The answer to this is the remains and waste products of plants, animals and other living things organisms.
I’m pretty sure it’s water, oxygen, and food. beacuse food provided both nutrients and an energy source.