There are 12 face cards and 4 aces to choose from. For the first card, the probability of drawing a face is
. Then the probability of drawing an ace second is
.
So the probability of drawing these two particular cards in the given order is
Answer:
p = 0.38, n = 20
The probability that he throws more than 10 strikes = 0.09233
Step-by-step explanation:
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = number of times Jack wants to bowl = 20
x = Number of successes required = number of strikes he intends to get
p = probability of success = probability that Jack throws a strike = 0.38
q = probability of failure = probability that Jack doesn't throw a strike = 0.62
P(X > x) = Σ ⁿCₓ pˣ qⁿ⁻ˣ (summing from x+1 to n)
P(X > 10) = Σ ²⁰Cₓ pˣ qⁿ⁻ˣ (summing from 11 to 20)
P(X > 10) = [P(X=11) + P(X=12) + P(X=13) + P(X=14) + P(X=15) + P(X=16) + P(X=17) + P(X=18) + P(X=19) + P(X=20)
P(X > 10) = 0.09233
There are binomial distribution cacalculators that can calculate all of this at once. Get one to minimize errors.
Which of what following? Is it suppose to be multiple choice?
(x, y)
Domain = x
Range = y
It is a function when none of the x values are repeating.
Answer - C) Both A and B
Hope this helps and makes sense!!
