Evaluate and simplify tan 15º.

1 answer:

6 0

Tan(15) = tan(45 - 30)

= [tan(45) - tan(30) ] / [ 1 + tan(30)tan(45)]

= (1 - 1/sqrt(3)) /(1 + 1/sqrt(3))

= (sqrt(3) - 1)/(sqrt(3) + 1)

= (sqrt(3) - 1)^2 /(3 - 1)

= 1/2 [3 + 1 - 2sqrt(3) ]

= (2 - sqrt(3) )

= 0.27 is your answer

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SOH CAH TOA -> $\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
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\\ \quad \\
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