All categories

2 years ago

8. A log is burning in a fireplace. If the amount of oxygen reaching the log is decreased, which of the

2 answers:

8 0

Answer: the reaction rate decreases.

Fire is the result of a combustion reaction, which is the reactionof the organic matter with oxygen. The rate is proportional to amountof oxygen. The, when the amount of oxygen that reaches the organic matter decreases, the rate of combustion decreases too.

EastWind [94]2 years ago

3 0

Answer is: The reaction rate decreases.

Balanced chemical reaction of burning log:

C(s) + O₂(g) → CO₂(g).

The reaction rate is the speed at which reactants are converted into products.

Reaction rate depends on concentration (amount) of oxygen.

If amount of oxygen decreases, reaction rate also decreases and vice versa.

You might be interested in

Vitamin C contains the elements C, H, and O. It is known to contain 40.9% C and 4.58% H by mass. The molar mass of vitamin C has

soldier1979 [14.2K]

Answer:

C₆H₈O₆

Explanation:

First off, the percent of oxygen by mass of vitamin C is:

100 - (40.9+4.58) = 54.52 %

Assume we have one mol of vitamin C. Then we would have 180 grams, of which:

180 * 40.9/100 = 73.62 grams are of Carbon

180 * 4.58/100 = 8.224 grams are of Hydrogen

180 * 54.52/100 = 98.136 grams are of Oxygen

Now we convert each of those masses to moles, using the elements' respective atomic mass:

C ⇒ 73.62 g ÷ 12 g/mol = 6.135 mol C ≅ 6 mol C

H ⇒ 8.224 g ÷ 1 g/mol = 8.224 mol H ≅ 8 mol H

O ⇒ 98.136 g ÷ 16 g/mol = 6.134 mol O ≅ 6 mol O

So the molecular formula for vitamin C is C₆H₈O₆

8 0

2 years ago

Benzoic acid, c6h5cooh, has a ka = 6.4 x 10-5. what is the concentration of h3o+ in a 0.5 m solution of benzoic acid? 3.2 x 10-5

FinnZ [79.3K]

The answer for this issue is:
The chemical equation is: HBz + H2O <- - > H3O+ + Bz-
Ka = 6.4X10^-5 = [H3O+][Bz-]/[HBz]
Let x = [H3O+] = [Bz-], and [HBz] = 0.5 - x.
Accept that x is little contrasted with 0.5 M. At that point,
Ka = 6.4X10^-5 = x^2/0.5
x = [H3O+] = 5.6X10^-3 M
pH = 2.25
(x is without a doubt little contrasted with 0.5, so the presumption above was OK to make)

3 0

3 years ago

Calculate the moles of calcium oxalate formed from 5 grams of potassium oxalate (molar mass 184.24 g/mol) the mole mole ratio fr

Nataly_w [17]

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).

We can calculate the moles of CaC₂O₄ obtained considering the following relationships.

The molar mass of K₂C₂O₄ is 184.24 g/mol.
The mole ratio of K₂C₂O₄ to CaC₂O₄ is 2:1.

$5 g K_2C_2O_4 \times \frac{1molK_2C_2O_4}{184.24gK_2C_2O_4} \times \frac{1molCaC_2O_4}{2molK_2C_2O_4} = 0.03molCaC_2O_4$

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Learn more: brainly.com/question/15288923

7 0

2 years ago

How could you determine if a tissue you are looking at could only be from the heart?

borishaifa [10]

You can determine it by paying attention to the unique characteristics that could only be found at heart's tissue, such as :

- looks striated or stripped
- The bundles are breached like tree but connected at both ends

hope this helps

6 0

2 years ago

Answer please!!!!!!!!!!!!!!!!!!!!!!!!✌✌✌

Nadya [2.5K]

Answer:

hxtististsy z7tzotz8tsx lhsitzrizrs ypzyztozkt udriztkzto

3 0

2 years ago