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2 years ago

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How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?

1 answer:

sveta [45]2 years ago

6 0

There are 6 digits. Each digit can take ten different numbers except for the first digit since it cannot be zero.

So:

9 x 10 x 10 x 10 x 10 x 10

900000 numbers.

Another way of thinking about this is to just count up to 999,999. Obviously there are 999,999 different numbers here. But since our number has to have 6 digits in them, we have to delete 99,999 numbers. Thus there are 900,000 different numbers.

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Researchers conducted a study to find out if there is a difference in the use of ereaders by different age groups. randomly sele

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Given sample 1 ( 29 years old) $n_{1}$ =628, $p_{1}$ =7%, sample 2( 30 years old) $n_{2}$ =2309, $p_{2}$ =0.11.

We have to first form hypothesis one null hypothesis and other alternate hypothesis.

$H_{0}:$ π1-π2=0

$H_{1}:$ π1-π2≠0

α=0.05

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The pooled proportion needed to calculate standard error is:

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The estimated standard error of difference between means is computed using the formula:

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= $\sqrt{0.000143+0.00003}$

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Z= Pd-(π1-π2)/ $S_{p_{1} -p_{2} }$

=-0.04-0/0.013

=-3.0769

This test is a two tailed test so the p value for this test is calculated as (using z table)

p value:2 P(Z<-3.0769)

=2*0.002092

=0.004189

P value< significance level of 5%.

Hence there is enough evidence to show the claim that there is a significant difference in the use of e readers by different age groups.

Learn more about hypothesis at brainly.com/question/11555274

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Question is incomplete as it also includes:

Significance level of 5%.

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