Answer:I do not know because there are no number in that equation sorry
:( :(
Step-by-step explanation:
Answer:
Our answer is 0.8172
Step-by-step explanation:
P(doubles on a single roll of pair of dice) =(6/36) =1/6
therefore P(in 3 rolls of pair of dice at least one doubles)=1-P(none of roll shows a double)
=1-(1-1/6)3 =91/216
for 12 players this follows binomial distribution with parameter n=12 and p=91/216
probability that at least 4 of the players will get “doubles” at least once =P(X>=4)
=1-(P(X<=3)
=1-((₁₂ C0)×(91/216)⁰(125/216)¹²+(₁₂ C1)×(91/216)¹(125/216)¹¹+(₁₂ C2)×(91/216)²(125/216)¹⁰+(₁₂ C3)×(91/216)³(125/216)⁹)
=1-0.1828
=0.8172
Answer: Canada Vegetation
Forests are primarily mixes of white and black spruce, lodgepole pine, balsam poplar, paper birch and trembling aspen. Common understorey plants include mountain and green alders, highbush cranberry, wild rose, Canadian buffalo berry and reed grass, fireweed, lingonberry, twinflower and feather mosses.
I’m not sure? But don’t answer the guy with the bitly it’s a scam
