Answer:
option c) 552 K is correct
Explanation:
we know that
0° C +273= 273 K
so
296° C+273=569 K
Answer:
Explanation:
NaCl = Na⁺ + Cl⁻
6120 ions of NaCl will contain 3060 ions of Na⁺ and 3060 ions of Cl⁻ , forming 3060 molecules of NaCl .
6.02 x 10²³ molecules of NaCl = 1 mole
3060 molecules of NaCl = 3060 x 10⁻²³ / 6.02 moles
= 508.30 x 10⁻²³ moles
= 5.08 x 10⁻²¹ moles
Answer : 5.08E-21 moles .
Explanation:
I) carbon dioxide
ii) nitrogen dioxide
iii) nitric acid
iv) sulphric acid
v) Potassium dichromate
vi) hexacyanoferrate (III) ion( not sure)
Answer: 4 molL-1
Explanation:
Detailed solution is shown in the image attached. The number of moles of NaCl is first obtained. Since the molarity must be in units of molL-1, the volume is divided by 1000 and the formula stated in the solution is applied and the answer is given to one significant figure.
Answer:
The magnesium atom loses 2 electron to the 2 atoms of chlorine. The 7 valency electrons of each chlorine atom will now be 8 to attain stable configuration. The final compound is written as MgCl2.
Explanation:
Ionic compounds are compound formed from the transfer of electron(s). One atom of the element loses electron(s) while the other atom gains electron(s).
The compound Magnesium chloride is an ionic compound . The bond between an atom of magnesium and 2 atoms of chlorine is an ionic bonding.
The valency electron of magnesium is 2 electron , for the atom of magnesium to attain octet rule, it will easily lose it 2 electrons to the chlorine atoms.
The chlorine atom on the other hand has 7 valency electrons, to attain octet configuration it will most likely gain 1 electron to become stable.
The magnesium atom loses 2 electron to the 2 atoms of chlorine. The 7 valency electrons of each chlorine atom will now be 8 to attain stable configuration. The final compound is written as MgCl2.