Answer:
100/10 = 10 , 10 × 10 = 100÷20 = 5
I'm pretty sure its wrong
The density of an object can be calculated using the formula Density = Mass/Volume.
Experimental Density:
Density = 153.8g / 20.00 cm^3
Density = 7.69g/cm^3
Percent error equation:
% Error = | Theoretical Value - Experimental Value|/Theoretical Value * 100
% Error = | 7.87g/cm^3 - 7.69g/cm^3|/7.87g/cm^3 * 100
% Error = 2.29%
Therefore a is the correct answer.
If it takes cool air and passes it through the heat source using a fan or blower, the type of heat transfer is convection heat transfer.
<h3>What is heat transfer by convection?</h3>
Convection is the transfer of heat from one place to another due to the movement of fluid.
During heat transfer by convection, cold air replaces hot risen air.
Thus, if it takes cool air and passes it through the heat source using a fan or blower, the type of heat transfer is convection heat transfer.
Learn more about convection here: brainly.com/question/893656
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Answer:
a. FALSE
b. FALSE
c. TRUTH
d. FALSE
e. FALSE
Explanation:
To determine which statements are truth or false you focus in the following formula, for the electric potential generated by a conducting sphere:
inside the sphere
for r > R (outside the sphere)
R: radius of the sphere
ε0: dielectric permittivity of vacuum
Q: charge of the sphere
As you can notice, inside the sphere the potential is constant. Inside the sphere, the potential is the same. Outside the surface the potential decreases as 1/r, being r the distance to the center of the sphere.
Hence, you can conclude:
a. The potential at the center of the sphere is zero. FALSE
b.The potential is lowest, but not zero, at the center of the sphere. FALSE
c. The potential at the center of the sphere is the same as the potential at the surface. TRUTH
d. The potential at the center is the same as the potential at infinity. FALSE
e. The potential at the surface is higher than the potential at the center. FALSE
If these are the missing choices:
<span>A. gritty navy blue surface.
B. bumpy red surface.
C. dull orange surface.
D. Polished pale yellow surface.
My answer: D. Polished pale yellow surface
I read an article that summarized the results of the emission of radiation experiments. It stated the following:
1) </span>Black surfaces are the best emitters of heat radiation.
2) Black surfaces are the best absorbers of heat radiation.
3) Shiny surfaces are the best reflectors of heat radiation.
4) Shiny surfaces are poor absorbers of heat radiation.
<span>5) Glass will not transmit long wave infra red radiation.
Because of the above summary, that is why I arrived at the answer D. Polished pale yellow surface would likely be the best reflector of heat energy.</span>
