Answer:
emulsion
Explanation:
An emulsion is a mixture of two or more liquids that are normally immiscible. Emulsions are part of a more general class of two-phase systems of matter called colloids.
Answer:
The pressure occupied is 1, 8 atm.
Explanation:
We use the Boyle´s Mariotte ´s law: for a given mass of gas at constant temperature, the pressure and volume vary inversely proportionally: P1xV1= P2xV2. The unit of pressure is converted to mmHg in atm.
760 mmHg----1 atm
912 mmHg---x= (912 mmHg x 1 atm)/760 mmHg=1,2 atm
P1xV1= P2xV2
P2=P1xV1/V2= 1,2 atm x 12 L/ 8L= <em>1, 8 atm</em>
Answer:
The electrons that participate in chemical bonds are the valence electrons, which are the electrons found in an atom 's outermost shell.
Explanation:
Answer:
the general equation is: A + X → AX. Where a single compound on the reactant side breaks down into two or more products during a chemical change. The general equation is AX → A + X.
Explanation:
Answer:
CH3CH2NH3+/CH3CH2NH2 would have the largest pKa
Explanation:
To answer this question we must know Kb of CH3CH2NH2 is 5.6x10⁻⁴, and for C6H5NH2 is 4.0x10⁻¹⁰. And the CH3CH2NH3+ and C6H5NH3+ are related with these substances because are their conjugate base. That means:
pKa of CH3CH2NH3+ = CH3CH2NH2; C6H5NH3+ = C6H5NH2
Also, Kw / Kb = Ka
Thus:
pKa of CH3CH2NH3+/CH3CH2NH2 is:
Kw / kb = Ka = 1.79x10⁻¹¹
-log Ka = pKa
pKa = 10.75
pKa of C6H5NH3+/ C6H5NH2 is:
Kw / kb = Ka = 2.5x10⁻⁵
-log Ka = pKa
pKa = 4.6
That means CH3CH2NH3+/CH3CH2NH2 would have the largest pKa
