The force that keeps the puck moving is 0.25 N while the velocity of the puck is 3.7 m/s.
<h3>What is the centripetal force?</h3>
We know that the centripetal force is the force that acts on a body that is moving along a circular path. In this case, we are told that the puck is moving along a circular path hence it is acted upon by the centripetal force that acts on it.
The centripetal force in this case would be supplied by the weight of the object that is moving in the circular path. Thus we can write in our equation that;
Centripetal force = Weight of object = mg
m = mass of the object
g = acceleration due to gravity
Then;
W = 0.026 Kg * 9.8 m/s^2
W = 0.25 N
To obtain the velocity of the object;
FT = mv^2/r
v = √ FT r/m
v = √0.25 * 1.4/0.026
v = 3.7 m/s
Learn more about centripetal force:brainly.com/question/11324711
#SPJ1
Answer:
It is an open circuit as the current isn't flowing through the circuit as the wires aren't connected
Answer:
24.3 m
Explanation:
Using the equation of motion
where s is the distance, u is initial velocity, t is time and a is acceleration
Substituting u for 6 m/s, t for 3 s, a for 1.4 m/s2 we obtain
Answer:
|X| = 72 cm
Explanation:
We need to find the magnitude of vector X.
Vector Y = 21 cm
Vector Z = 75 cm
We know that, the magnitude of resultant vector is given by :
So, the value of magnitude of vector X is 72 cm
