Question

What is the range of the function y=square x+5

Answer 1

The "range" here means the restrictions of y.

You should know for y = sqrt(x) function, it's range is y >=0

Here it's the same thing.

Answer 2

Answer:

Option B is correct.

The range of the function is $y\geq 0$

Explanation:

The function y=f(x) =$\sqrt{x+5}$

The range of a function y=f(x) is the set of values y takes for all values of x  within the domain of y=f(x).

The domain of given function f(x) is the set of all values of x in the interval $[-5, \infty)$

As x takes values from -5 to $+\infty$,

then, $\sqrt{x+5}$ takes values from $\sqrt{0}$ =0 to $\sqrt{+\infty}$

Therefore, the range of the y=$\sqrt{x+5}$ is given by: $[0, \infty)$ or we can also write it as $y\geq 0$