All categories

3 years ago

A non-magnetized metal object can be magnetized with a stronger magnet. Explain how this happens on the atomic level.

Chemistry

1 answer:

sergeinik [125]3 years ago

6 0

I believe the atomic level increases hope this helps.

You might be interested in

Please help me I will give you the brain thing with extra points if you help me, please. I need to get this right. 3/10

Cerrena [4.2K]

Answer:

I'd say its speed but not to sure

Explanation:

5 0

2 years ago

Examine the incomplete statement.

hjlf

Answer: Option (c) is the correct answer.

Explanation:

In liquids, molecules are held by slightly less strong intermolecular forces of attraction as compared to solids.

Hence, molecules of a liquid are able to slide past each other as they have more kinetic energy than the molecules of a solid.

As a result, liquids are able to occupy the shape of container in which they are placed. Also, liquids have fixed volume but no fixed shape.

Thus, we can conclude that liquids have a variable shape and a fixed volume.

5 0

2 years ago

Read 2 more answers

Write the formula and determine the percent by mass of the salt in barium hydroxide octahydrate *

user100 [1]

Answer:

315.51g/mol

Explanation:

137(33 + (16.00 + 1.01) 2 + 8 [1.01 (2) + 16.00] = 315.51g/mol

7 0

1 year ago

Which of the following describes the correct order for using the scientific

larisa [96]

A. is the answer
if u have any doubts ask me
please mark as brainliest

8 0

2 years ago

Read 2 more answers

Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of

bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

$O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol$ ..[1]

$O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol$ ..[2]

$NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol$ ..[3]

$NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?$ ..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

$2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}$

$2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol$

$2\times \Delta H^o_{4}=470.3 kJ/mol$

$\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol$

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0

2 years ago