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2 years ago

What is the simplified form of the fraction below ? 5/15

Mathematics

2 answers:

ale4655 [162]2 years ago

8 0

Answer:

1/3

Step-by-step explanation:

first find a common denominator. in this case its 5. now divide both the numerator and denominator by 5 and there you go :)

zhenek [66]2 years ago

5 0

Answer:

1/3

Step-by-step explanation:

A fraction consists of two parts: The numerator and denominator.

In order to simplify the fractions, we check that the numerator and the denominator are multiples of which same number.. For example, for the fraction 2/6, we observe that the numblerator and denominator both are a multiple of 2 so will be simplified to 2*1/2*3 = 1/3.

Now,

For the given fraction,

=>5/15

As we can easily see that both the numerator and denominator are a multiple of 5,

=> 5/15 = 5*1/5*3

The 5 in the numerator and denominator will be cancelled so the simplified fraction is 1/3..

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A protein mix claims to contain a bonus of 20% more mix than the usual size container. If the bonus size contains 18 ounces of m

agasfer [191]

Answer:

The usual size of the container is 15 ounces.

Step-by-step explanation:

Consider the provided information.

A protein mix claims to contain a bonus of 20% more mix than the usual size container.

Let the usual size of the container was x ounces.

They increase 20% of usual size and the bonus size is 18 ounces.

Therefore, the new size should be:

$x+20\%x=18$

$x(1+0.20)=18$ (∴20%= $\frac{20}{100}$ =0.20)

$x(1.20)=18$

$x=\frac{18}{1.20}$

$x=15$

Hence, the usual size of the container is 15 ounces.

3 0

2 years ago

Let Z={a,c,{a,b}}. What is |Z|?

Lina20 [59]

$Z=\{a,c,\{a,b\}\}$

$\boxed{|Z|=3}$ (treat $\{a,b\}$ as one element of $Z$ )

The power set of $Z$ is

$\boxed{2^Z=\bigg\{\{\},\{a\},\{c\},\big\{\{a,b\}\big\},\{a,c\},\big\{a,\{a,b\}\big\},\big\{c,\{a,b\}\big\},\big\{a,c,\{a,b\}\big\}\bigg\}}$

1. $\{a,c\}\subseteq Z$ is true because both $a\in Z$ and $c\in Z$ .

2. $a\in Z$ is true.

3. $\{c\}\subseteq Z$ is true (same reason as part 1).

4. $\{c\}\in Z$ is false because $Z$ does not contain the set $\{c\}$ , rather just the element $c$ itself.

5. $b\in Z$ is false because the element $b$ on its own simply is not in $Z$ . That $b\in\{a,b\}$ does not mean $b\in Z$ , but that $b$ belongs to a subset of $Z$ .