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2 years ago

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PLEASE HELP with these math questions (Please don't answer if you don't know all of them)

1 answer:

Leona [35]2 years ago

5 0

Sqrt (53) = 10 * sqrt (0.53)

0.53 = 64/121
sqrt (0.53) = sqrt (64)/ sqrt (121) = 8/11 = 0.7273
Therefore sqrt (53) = 10 * 0.7273 = 7.27

sqrt (108) = 10 * sqrt (1.08)
sqrt (1.08) = sqrt (676/625) = 26/25 = 1.04
Therefore sqrt (108) = 10 * 1.04 = 10.4

sqrt (128) = 10 * sqrt (1.28)
sqrt (1.28) = sqrt (289/225) = 17/15 = 1.133
Therefore sqrt (108) = 10 * 1.133 = 11.33

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Help Me out with this question plz thx

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Answer:

6x³ - 8x + 9

Step-by-step explanation:

Step 1: Write out expression

2x + 7 + 6x³ - 1 + 3 - 6x - 4x

Step 2: Combine like terms (x)

6x³ - 8x + 7 - 1 + 3

Step 3: Combine like terms (constants)

6x³ - 8x + 9

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2 years ago

Read 2 more answers

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2 years ago

Mr. Ramirez orders drumsticks and sheet music for a group of students. One pair of drumsticks costs $1. 50, and the sheet music

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Answer:

Step-by-step explanation:

It expresses how much money he had to pay in total for the sheet music and drumsticks altogether.

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1 year ago

Find the slope-intercept form of the equation of the line that passes through the point P and makes angle with the positive x-

SIZIF [17.4K]

Answer:

The answer is " $y= -x+7$ "

Step-by-step explanation:

If $\bold{\theta = 135^{\circ}}$

point: $p=(2,5)$

Formula:

$\to m= \tan \theta \\\\\to (y-y_1)= m(x-x_1)$

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2 years ago

Javier's parents set an amount of money aside when he was born. They earned 4.5% simple interest on that money each year. When J

solmaris [256]

Answer:

Javier's parents set aside $1500 when he was born

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

$E = P*I*t$

In which E is the interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

In this question, we have that:

$E = 1012.50, t = 15, I = 0.045$

We have to find P. So

$E = P*I*t$

$1012.50 = P*15*0.045$

$P = \frac{1012.50}{15*0.045}$

$P = 1500$

Javier's parents set aside $1500 when he was born

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2 years ago