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2 years ago

What is the reflection image of p(0, 0) after two reflections, first across x = -3 and then y = 4 ?

Mathematics

1 answer:

Butoxors [25]2 years ago

3 0

The reflection point P' would be (-6, 8)

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Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

5 0

2 years ago

What is the solution to the system of equations graphed below? y=-4x + 33 y=5/3x-1

Black_prince [1.1K]

Answer:

x = 6

y = 9

This is the correct answer. Not satisfied? Check out this answer expert verified answer of the same question but with a step-by-step explanation. This answer is just a simple version of rocioo's correct answer.

Expert Verified Answer (of this same question but with a step-by-step explanation):

This is the link to rocioo's answer. brainly.com/question/13675950

3 0

2 years ago

Read 2 more answers

The area of a square with sides of 2 feet is 4 square feet. The area of a square with sides of 4 feet is 16 square feet. What eq

sattari [20]

X^2=area of a square

x squared equals the area of a square

3 0

2 years ago

Solve: |x+2|=3 Can someone explain how to do this

katovenus [111]

Hey there!

ORIGINAL EQUATION:
|x + 2| = 3

TRANSLATE:

x + 2 = 3 or x + 2 = -3

SOLVING for: x + 2 = 3

SUBTRACT 2 to BOTH SIDES

x + 2 - 2 = 3 - 2

CANCEL out: 2 - 2 because it give you 1

KEEP: 3 - 2 because help solve for the current x-value

NEW EQUATION: x = 3 - 2

SIMPLIFY IT!
x = 1

Thus, your answer is: x = 2

/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\

SOLVING for: x + 2 = -3

SUBTRACT 2 to BOTH SIDES

x + 2 - 2 = -3 - 2

CANCEL out: 2 - 2 because it give you 0

KEEP: -3 - 2 because it help solve for the current x-value

NEW EQUATION: x = -3 - 2

SIMPLIFY IT!
x = -5

Thus, your answer is: x = -5

/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\

Therefore, your answer is: x = 1 or x = -5

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

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1 year ago

The coordinates (-1,6) represent which point?

Elena-2011 [213]

b is the correct anwser

6 0

2 years ago