Factors of 84: 1, 2<span>, </span>3<span>, 4, 6, </span>7<span>, 12, </span>14<span>, </span>21<span>, </span>28<span>, </span>42<span>, 84. Prime factorization: 84 = </span>2<span> x </span>2<span> x </span>3<span>x </span>7<span> which can also be written (</span>2^2<span>) x </span>3<span> x </span>7<span>.</span>
I am left Handed!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
I think the answer is 2x10^1
Answer: a) 1082, b) wider.
Step-by-step explanation:
Since we have given that
Margin of error = 0.1 millimeter = E
Standard deviation = 2 mm = σ
Critical value would be
a) Sample size would be
b) Sample size, n = 100
So, the margin of error would be
Since the margin of error in b part is more than a part, as we know that the higher the margin of error, the wider the confidence interval.
So, it would have wider confidence interval.
Hence, a) 1082, b) wider.