Question

Help me with B please

Answer 1

Area of each piece of paper is $8\frac{1}{2}\times11=\frac{17}{2}\times11=\frac{187}{2}$

Greatest number of possible piece of paper is $[1000\div\frac{187}{2}]=[1000\times\frac{2}{187}]=[\frac{2000}{187}]=10$