We have that
<span>points A (-5, 6) and B (7, -1)
Part A)
find the distance
d=</span>√[(y2-y1)²+(x2-x1)²]-------> d=√[(-1-6)²+(7+5)²]----> d=√(49+144)
d=√193 units
Part B)
find the midpoint
ABx=(x1+x2)/2-----> (-5+7)/2-----> ABx=1
ABy=(y1+y2)/2-----> (-1+6)/2-----> ABy=2.5
the midpoint is (1,2.5)
Part C)
find the slope
m=(y2-y1)/(x2-x1)-----> m=(-1-6)/(7+5)--------> m=-7/12
the slope m=-7/12
0.12 because it equals to 12% where 1.2% equals to 0.012
Answer:
∠Q = 75°
Step-by-step explanation:
Start by recognizing that the triangle is isosceles (the long sides are marked as being equal-length). That means angles Q and R have the same measure.
Next, you use the fact that the sum of angles is 180° to write an equation.
∠R +∠P +∠Q = 180°
(2x +15)° +x° +(2x +15)° = 180° . . . . substitute the known values
5x +30 = 180 . . . . . . . . . . . . . . . . divide by °, collect terms
5x = 150 . . . . . . . . subtract 30
x = 30 . . . . . . . divide by 5
Then angle Q is ...
∠Q = (2x +15)° = (2×30 +15)°
∠Q = 75°
