<span>x intercept when f(x) = 0
so
</span><span>x^2-81 = 0
x^2 = 81
x = + 9 and x = -9
Answer
</span><span>C -9</span>
Answer:
(2,5)
Step-by-step explanation:
The rule to 90 degrees about the origin is (x,y) to (-y,x). You basically switch the values of y and x but remember the value of y is negative. The value of y is -2 so -2 is now 2 since the rule changed the sign (-2×-y=2) and 5 isnt affected except it is the x value. Just know that since they r switched, x is now 2 and y is 5 when rotated 90 degrees about the origin.
Answer:
Let's define all the possible forms:
slope-intercept: y = a*x + b
point-slope: y - y1 = a*(x - x1) (where (x1, y1) is a point in the line)
standard form: a*x + b*y = c
then:
a) 7x + 5y = 8
This is in standard form.
b) y − 5 = 3*(x − 9)
This is in point slope form.
c) y = 7x + 9
This is in slope-intercept form.
d) 8x − 9y = −2
This is in standard form.
Substitute the value of x into the function;
f(0.25)=1/3(-5(0.25))
f(0.25)=1/3(-5(1/4))
f(1/4)=1/3(-5/4)
f(1/4)=-5/12
Therefore, the function would be at -5/12 when x=1/4
Hope I helped :)
2,3,5! 1 is NOT a prime number!
