The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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Based on the fact that Sienna has read 60 pages, we can infer that Micha has read 375 pages of the book.
Sienna has read 40% of what Rhys has read and that corresponds to 60 pages. The number of pages read by Rhys is therefore:
<em>= Number of pages / Percentage read </em>
= 60 / 40%
= 150 pages
The 150 pages read by Rhys is 40% of what Micah has read. Micah has therefore read:
= 150 / 40%
= 375 pages
In conclusion, Micah has read 375 pages.
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(10+t)/(18+t)=8/10
8(18+t)=10(10+t)
144+8t=100+10t
44=2t
t = 22 throws
Answer: -x+8
explanation: it’s in its simplest form because it cannot be factored
Step-by-step explanation:
80 times 2 is 160
Therefore, 100 times 2 is 200
You multiply the denominator and numerator by the same number.