Ask question

Ask question

All categories

3 years ago

15

Pretty simple question but im stupid and need assistance

1 answer:

malfutka [58]3 years ago

4 0

the second one I think don't get mad if it is wrong please

You might be interested in

5 star rating help quick

tangare [24]

Answer:

i think b

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Use partial fraction expansion to evaluate: LaTeX: \int\frac{x-1}{x^2+3x+2}dx ∫ x − 1 x 2 + 3 x + 2 d x a. LaTeX: -2\ln\left|x+1

ohaa [14]

$\frac{x-1}{x^2+3x+2}\\\frac{x-1}{(x+1)(x+2)}\\\frac{x-1}{(x+1)(x+2)}=\frac{A}{x+2}+\frac{B}{x+1}\\x-1=A(x+1)+B(x+2)\\\\\text{ Let } x=-1 \text{ then } -2=A(0)+B(-1+2) \text{ which means } B=-2\\\\\text{ Instead of choose } x \text{ to be -1, let's now set it equal to -2 to find } A\\\\-3=A(-1)+B(-2+2)\\-3=-A\\A=3\\\\ \text{ So your integral becomes } \\\int \frac{3}{x+2} dx+\int \frac{-2}{x+1} dx\\3 \ln|x+2|-2\ln|x+1|+C\\\\or\\-2\ln|x+1|+3\ln|x+2|+C$

8 0

2 years ago

How would #8 be written out

Alecsey [184]

It would be written out as "number eight".

4 0

2 years ago

Read 2 more answers

Ares of a rectangular floor of your house is Ax+5x-2. if the length is x+2 units, find A

Snezhnost [94]

Answer:

A=4.

Step-by-step explanation:

Note: In the expression of area the first term should be $Ax^2$ .

It is given that area of a rectangular floor of your house is $Ax^2+5x-2$ and the length is $(x+2)$ units.

We know that, area of a rectangle is

$Area=length\times width$

Since length of the rectangle is $(x+2)$ , therefore $(x+2)$ is a factor of $Ax^2+5x-2$ and the value of $Ax^2+5x-2$ is 0 at x=-2.

$A(-2)^2+5(-2)-2=0$

$4A-10-2=0$

$4A-12=0$

$4A=12$

Divide both sides by 4.

$A=4$

Therefore, the value of A is 4.

7 0

2 years ago

What’s ratio less than 15/24?

Musya8 [376]

Answer:

the ratio less than 15/24 can be 1:2, 7:8

4 0

2 years ago