Answer:
Let L(n) be the function that gives the amount of logs stacked after n loads.
L(n) = 12 + 8(n-1)
Step-by-step explanation:
Let L(n) be the function that gives the amount of logs stacked after n loads.
Let's call for the moment the first load as L(0)
L(0)= 12
Let r be the number of logs carried in each load, then
L(n) = 12 + nr
Since L(6) (the seventh load) equals 60, we have
60 = 12 + 6r, and r = 8.
So a function for the number of loads starting from n=0 would be
L(n) = 12 + 8n
If we want to start with n=1, we simply change the variable
L(n) = 12 + 8(n-1) (n=1,2,3,...).
So L(1) = 12, L(2) = 20, L(3) = 28,...L(7) = 60 and so on.
simplify the expression (4g^10)^4
<h2><em><u>
A.256g^40</u></em></h2>
B. 4g^40
C.256g^14
Answer:
The relationship is that if you divide say, 88÷4=22 the relationship is that all of them divided would equal 22.
Hope this helped.
Answer:
So the answer for this case would be n=22547 rounded up to the nearest integer
Step-by-step explanation:
Let's define some notation
represent the sample mean
population mean (variable of interest)
represent the population standard deviation
n represent the sample size
represent the margin of error desire
The margin of error is given by this formula:
(a)
And on this case we have that ME =+1 and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
The critical value for 99% of confidence interval now can be founded using the normal distribution. The significance would be and the critical value , replacing into formula (b) we got:
So the answer for this case would be n=22547 rounded up to the nearest integer
Changing the h value will move the graph horizontally left or right.