This is not a polynomial equation unless one of those is squared. As it stands x=-.833. If you can tell me which is squared I can help solve the polynomial.
Ok, that is usually notated as x^3 to be clear. I'll solve it now.
x^3-13x-12=0
Then use factor theorum to solve x^3-13x-12/x+1 =0
So you get one solution of x+1=0
x=-1
Then you have x^2-x-12 now you complete the square.
Take half of the x-term coefficient and square it. Add this value to both sides. In this example we have:
The x-term coefficient = −1
The half of the x-term coefficient = −1/2
After squaring we have (−1/2)2=1/4
When we add 1/4 to both sides we have:
x2−x+1/4=12+1/4
STEP 3: Simplify right side
x2−x+1/4=49/4
STEP 4: Write the perfect square on the left.
<span>(x−1/2)2=<span>49/4
</span></span>
STEP 5: Take the square root of both sides.
x−1/2=±√49/4
STEP 6: Solve for x.
<span>x=1/2±</span>√49/4
that is,
<span>x1=−3</span>
<span>x2=4</span>
<span>and the one from before </span>
<span>x=-1</span>
Answer:
t = (C - 3*A)/B + 3
Step-by-step explanation:
Given in the question that,
the speed with which canoe travelled for first 3 hours = A
the speed with which he travelled for any and all time thereafter = B
As we do not know the values of A, B, or C, so the answer will be an expression for C in terms of A and B.
<h3>Formula to use</h3>
distance = speed x time
C = A*3 + B*(t-3)
Rearranging and solving for t
C - (A*3) = B*(t-3)
C - (A*3) = Bt - B3
C - (A*3) + B3 = Bt
t = C - (A*3) + B3 / B
or
t = (C - 3*A)/B + 3
Answer:
BC 4 in
Step-by-step explanation:
The steps for construction;
- Using a ruler draw line AB 4 inches and label the end points A and B
- At point A , using a protractor, measure angle 60° and mark with point. Draw a line from A passing through this point extending to a length of 4 inches
- Mark that point C.
- Using the ruler, join point C and B and measure BC.
From calculation, length BC can be found by the formula;
------where a=b=4 in , cos A = cos 60°
BC = 4 in
Answer: Classic beauty.
Step-by-step explanation: ...
