Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em><em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em><em>, where </em><em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:
(1)
By Quadratic Formula:
,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Answer:
15 x^8 y^3
Step-by-step explanation:
The area of a rectangle is given by
A = l*w where l is the length and w is the width
A = ( 5x^6 y^2) *( 3x^2 y)
= 15 x^(6+2) y^(2+1)
= 15 x^8 y^3
For the lunch it would be 20$
Answer- 30
Step-by-step explanation: