What is the value of b2 - 4ac for the following equation? x 2 + 5x + 4 = 0

The length of a rectangular is 7/10 ft .and the width is 1/5ft what is the perimeter

Blababa [14]

<h3>Answer:</h3>

$\huge\boxed{1 \frac{4}{5}\ \text{ft}}$

<h3>Explanation:</h3>

Change $\frac{1}{5}$ so that is has a common denominator. $\frac{1*2}{5*2}=\frac{2}{10}$

Make an equation. $\frac{7+7+2+2}{10}$

Add. $\frac{14+4}{10}$

Add. $\frac{18}{10}$

Divide both sides by 2. $\frac{9}{5}$

Convert to a mixed number. $1 \frac{4}{5}$

4 0

2 years ago

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Can someone please help me

PtichkaEL [24]

Answer:

The size is 37.5 degrees

Step-by-step explanation:

The total angle in the triangle is 180

Since the other two angles are congruent. it means that they are equal

Let us call each of the angles x

Mathematically,

x + x + 105 = 180

2x = 180-105

2x = 75

x = 75/2

x = 37.5

7 0

2 years ago

(5x^3-8x^2+9x+12)/(x-3)<br><br> please answer with sentences on how to do it step by step. thanks!

Anastaziya [24]

Answer:

$5x^2+7x+30+\frac{102}{x-3}$

Step-by-step explanation:

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}5x^3-8x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{5x^3}{x}=5x^2\\\mathrm{Quotient}=5x^2\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}5x^2:\:5x^3-15x^2\\\mathrm{Subtract\:}5x^3-15x^2\mathrm{\:from\:}5x^3-8x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=7x^2+9x+12\\\mathrm{Therefore}\\=5x^2+\frac{7x^2+9x+12}{x-3}$

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}7x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{7x^2}{x}=7x\\\mathrm{Quotient}=7x\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}7x:\:7x^2-21x\\\mathrm{Subtract\:}7x^2-21x\mathrm{\:from\:}7x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=30x+12\\\mathrm{Therefore}\\=5x^2+7x+\frac{30x+12}{x-3}\\$

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}30x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{30x}{x}=30\\\mathrm{Quotient}=30\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}30:\:30x-90\\\mathrm{Subtract\:}30x-90\mathrm{\:from\:}30x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=102\\\mathrm{Therefore}\\=5x^2+7x+30+\frac{102}{x-3}$

6 0

2 years ago

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Factor completely 5c5 + 60c4 + 180c3.

Mrac [35]

5c^5 + 60c^4 + 180c^3

find the GCF, 5c³

5c³(5c^5 + 60c^4 + 180c^3/ 5c^3)

5c³(c² + 12c + 36)

5c³(c² + 2(c)(6) + 6²)

5c³(c + 6)² <<< the answer.

hope this helps, God bless!

8 0

2 years ago

11 students went on a trip to New York City. 3 of them visited the Statue of Liberty. What fraction of the students visited the

Ne4ueva [31]

so since only 3 out of 11 went to visit then it is simple

since just 3 went and there were 11

3/11 of the students went

5 0

2 years ago

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