Answer:
Step-by-step explanation:
RS + ST = RT
6y + 3 + 4y + 7 = 60
6y + 4y + 3 + 7 = 60
10y + 10 = 60
10y = 60 - 10
10y = 50
y = 50/10
y = 5
RS = 6*5 + 3 = 30 +3 = 33
ST = 4*5 + 7 = 20 + 7 = 27
Answer:
The range of the 95% data (X) = 238.3 days < X < 289.9 days
Step-by-step explanation:
Given;
mean of the normal distribution, m = 264.1 days
standard deviation, d = 12.9 days
between two standard deviation below and above the mean is 96% of all the data.
two standard deviation below the mean = m - 2d
= 264.1 - 2(12.9)
= 238.3 days
two standard deviation above the mean = m + 2d
= 264.1 + 2(12.9)
= 289.9 days
The middle of the 95% of most pregnancies would be found in the following range;
238.3 days < X < 289.9 days
Answer:
X=3
Step-by-step explanation:
Hope this helps and have a wonderful day!!!
Answer:
the solution is (2, -6)
Step-by-step explanation:
Substitute the second equation into the first, replacing y in the first:
2x - (-4x+2) = 10
Simplifying, we get:
2x + 4x - 2 = 10, or:
6x = 12, which yields x = 2.
Substituting 2 for x in the second equation yields y = -4(2) + 2 = 0, or y = -6
Then the solution is (2, -6).
Tan A = BC/AB = 15/8
answer is B. 15/8
